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aalyn [17]
3 years ago
11

I have a question where I need to add the mixed numbers 5 3\8 and 3 2\5 using a model and number line I have absolutely no idea

how to do this, can you help me
Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

8\frac{31}{40}

Step-by-step explanation:

In representing mixed numbers on a number line, we need first to pay attention to the denominators. Here, denominators are 8 and 5, their least common multiple is 40, so, we will need to cut up space between two numbers on the number line on 40 pieces. Also, we have 5 and 3 wholes at these mixed numbers, so, our answer is going to be  greater than 8.

We will cut the space between 8 and 9 on a number line on 40 pieces, and we will add \frac{3}{8} and \frac{2}{5} and get :

\frac{3}{8} +\frac{2}{5} = \frac{15}{40} +\frac{16}{40} =\frac{31}{40}

So, on  a number line between 8 and 9 we need to count 31 out of 40 pieces and that is the result, 8 wholes and \frac{31}{40}.

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A) 1,360cm<br> B) 1,632cm<br> C) 408cm<br> D) 816cm
Rashid [163]

Answer:

The answer is B

Step-by-step explanation:

The volume of a triangular prism is

v =  \frac{bh}{2} . \: 1

Where b = 12cm, h = 8cm, and I = 34

v =  \frac{12.8}{2} . \: 34

V = 1,632 (cm) ³

3 0
3 years ago
Help pls .. Shifted down 1 unit and to the right 2
Lapatulllka [165]

Answer:

g(x) = (x - 2) ^{2}  - 1

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5 0
3 years ago
Help me with this question
Ivan

B is the answer because none of the others will be right and b is the one you should always do when to solve a rea word problem

8 0
3 years ago
Evaluate the expression for d = 43.4.
denpristay [2]

Answer:

36.96

Step-by-step explanation:

given

d = 43.4

equation

4.4(d - 35) =

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5 0
4 years ago
PLEASE HELP ME, I HAVE NO IDEA! Find an equation for the line below.
irga5000 [103]

9514 1404 393

Answer:

  y -2 = -2/3(x +4)

Step-by-step explanation:

There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.

That form is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

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The two marked points are (-4, 2) and (5, -4). All we need is the slope.

The slope is given by the formula ...

  m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)

  m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3

Using the first point, the equation for the line can now be written as ...

  y -2 = -2/3(x -(-4))

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8 0
3 years ago
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