I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the -5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5)(x+1)=0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1
Okay here:
Let L be the length and W the width of the rectangle.
1. w=2•L
2. 2L+2W=36
Substitute eq. 1 into eq. 2,
2L+2•(2•L)=36
2L+4L=36
6L=36
L=9
Not done yet, then from eq. 1,
W=2•L
W=2•9
W=18 <------- Your answer. :)
Answer:
-25 and 2
Step-by-step explanation:
x + y = -23
xy = 50, so y = 50 /x
.
x + 50/x =-23, x^2 +23x - 50 = (x-2)(x+25)
so 2 and -25
Answer:
5*
Step-by-step explanation:
We have that
[(4x+2)/(x+5)]-[(3x+1)/(x+5)]
<span>They have common denominators, so just add the numerators like normal fractions:</span>
=[(4x+2)-(3x+1)]/(x+5)
=[(4x+2-3x-1)]/(x+5)
=[(x+1)]/(x+5)
the answer is
(x+1)/(x+5)
