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andrezito [222]
3 years ago
12

Let 3.27<<5.89 represent an interval on the number line. Find the value that is in the middle of the interval.

Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

The middle value of the interval is 4.58

Step-by-step explanation:

Consider the provided interval.

We need to find the value that is in the middle of the interval.

We can find the middle value of the interval by adding the upper and lower limit and divide the sum of the upper and lower limits by 2.

Here the upper limit is 3.27 and lower limit is 5.89.

\frac{3.27+5.89}{2}=\frac{9.16}{2}=4.58

Hence, the middle value of the interval is 4.58

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True or False? The graph of sine can be used to construct the graph of the secant function.
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True

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Since there is a great similarity between the sine and cosine graphs, and the secant graph is an inverse of the cosine graph, the graph of sine can be used to construct the graph of the secant function

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since  sec x  =  1 / cos x

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Learn more here: brainly.com/question/9554579

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3 years ago
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Multiple or divide as indicated 2x/4x+2 x 14 x+7/6
otez555 [7]
<span>2x/4x+2 x 14 x+7/6 is unclear.  Do you mean 2/4x, or do you mean  2x
                                                                                                           --------  ??
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I will assume that you meant to write

   2x
--------- * 14x + 7/6
4x + 2

but am very much unsure if this is correct or not.



Perhaps you meant 

</span>2x/(4x+2) times 14(x+7/6)
<span>
This comes out as follows:

 2x * 14 (x + 7/6)        28x(x + 7/6)        14x(x + 7/6) 
------------------------ = ------------------- = --------------------
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Performing the multiplication, we get            14x^2 + 98/6
                                                                     --------------------
                                                                              2x+1
</span>  

It appears that you're using "x" both as a variable name and as the "multiply" operator.  If so, please don't!  Use " * " to indicate multiplication.
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