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Bess [88]
3 years ago
6

SOLVING INEQUALITIES UNIT PORTFOLIO

Mathematics
1 answer:
noname [10]3 years ago
6 0

Answer:

Step-by-step explanation:

I don't really know sorry I am not smart I only sign up to see the answers

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C. A parallelogram
Oxana [17]

If a parallelogram has an area of 7 square units, and the height corresponding to a base is (\frac{1}{4}) units, then the base is 28 units.

As per the question statement, a parallelogram has an area of 7 square units, and the height corresponding to a base is (\frac{1}{4}) units.

We are required to find out the base of the parallelogram.

To solve this question, we need to know the formula to calculate the area of a parallelogram, which goes as

Area of Parallelogram = (Base * Height)

Putting our data obtain from the question statement, in the above-mentioned formula, we can calculate the value of the base of our concerned parallelogram, i.e.,

7=(base*\frac{1}{4})\\or, base=(7*4)\\or, base = 28
Therefore, base of our concerned parallelogram is 28 units.

  • Parallelogram: In Euclidean geometry, a parallelogram is a four-sided, plane, closed figure (Quadrilateral) with two pairs of parallel, opposite sides.

To learn more about Parallelograms, click on the link below.

brainly.com/question/16052466

#SPJ9

7 0
1 year ago
PLEASE HELP!!
Bezzdna [24]

Answer:

y=-\dfrac{9}{40}x^2+\dfrac{441}{40}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

y=ax^2+b

This parabola passes through the point R(3,9), then

9=a\cdot 3^2+b\\ \\9=9a+b

The area of the right triangle PQR is

A_{PQR}=\dfrac{1}{2}\cdot PQ\cdot QR

Find PQ and QR, if P(x_1,0),\ Q(3,0),\ R(3,9):

PQ=\sqrt{(x_1-3)^2+(0-0)^2}=|x_1-3|\\\\QR=\sqrt{(3-3)^2+(0-9)^2}=9

Now,

40.5=\dfrac{1}{2}\cdot |x_1-3|\cdot 9\\ \\90=9|x_1-3|\\ \\|x_1-3|=10\\ \\x_1-3=10\ \text{or}\ x_1-3=-10\\ \\x_1=13\ \text{or }x_1=-7

We get two possible points P_1(-7,0) and P_2(13,0).

For point P_1:\\

0=a\cdot (-7)^2+b\\ \\49a+b=0

So,

b=-49a\\ \\9=9a-49a\\ \\-40a=9\\ \\a=-\dfrac{9}{40}\\ \\b=\dfrac{441}{40}\\ \\y=-\dfrac{9}{40}x^2+\dfrac{441}{40}

For point P_2:\\

0=a\cdot (13)^2+b\\ \\169a+b=0

So,

b=-169a\\ \\9=9a-169a\\ \\-160a=9\\ \\a=-\dfrac{9}{160}\\ \\b=\dfrac{1,521}{160}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}

5 0
3 years ago
Five hundred fifty students attended the assembly. If the ratio of boys to girls in the assembly was 6 to 5, how many girls atte
aivan3 [116]

Step-by-step explanation:

let, the ratio of boys and girls be 6x:5x

total student=550

now,

  • 6x+5x=550
  • 11x=550
  • x=550/11
  • x=50

<h3>number of girls who attended the assembly are 5x=5×50=2</h3><h2 /><h2>hope it helps.</h2>
7 0
3 years ago
Read 2 more answers
I GIVE YOU BRAINLIEST IF YOU HELP ME WITH THIS. Please guys I beg. I'm the dumbest person on earth.
MrRissso [65]

Answer:

You didn't even post the question how are we supposed to help you

Step-by-step explanation:

8 0
3 years ago
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When Debbie baby-sits, she charges $5 to go to the house plus $8 for every hour she is there. The expression 5+ 8h gives the amo
makvit [3.9K]
She will charge $45 for 5 hours

7 0
3 years ago
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