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lesya [120]
3 years ago
12

Which shows all the like terms in the expression? 4x -3+7x + 1

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
It’s 11x -2 And I couldn’t find a explanation sorry
vaieri [72.5K]3 years ago
6 0

Answer:

4x and 7x; -3 and 1: these are like terms

Step-by-step explanation:

when finding like terms, look for same variables.

You might be interested in
Samuel solved the equation h - 234 = 1,192 and found the solution to be h = 958. Is he correct? If not, why not?
prohojiy [21]

Answer:

B.

Step-by-step explanation:

h -234 = 1,192

-234 is a negative and if you add a negative number with a positive you have subtract and the remaining is your answer.

1,192+234=1,426

1,426-234=1,192

h=1,426



4 0
3 years ago
How do I solve y=x+3​
Lena [83]

You can use a <u>graph calculator</u>, if you don’t have one use the app <u>Photomath</u> to help.

4 0
3 years ago
Read 2 more answers
6 pipes can fill a reservoir in 24minutes.one pipe can fill it in
Hunter-Best [27]
The answer to your question is 4 minutes
3 0
4 years ago
Will give brainliest <br> What is the output of y=6x−11 when the input is 5?
MrRissso [65]

Answer:

19

Step-by-step explanation:

y = 6x - 11     If x = 5

y = (6*5) - 11

y = 30 - 11

y = 19

5 0
3 years ago
Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

8 0
3 years ago
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