Which statements are true about making formatting changes to cells in Excel? (Select all that apply)

Super easy question but you have to think about it because it’s not that easy I’ll mark brainliest for first answer Explain the

kkurt [141]

Answer:

Databases are not that simple. Now we not only have a Data warehouse, but we also have the Data Lake as well. We also have NoSQL and SQL form of support with these modern databases. The JSON format is rocking. You can hence through JSON store the text, image, audio, video, etc in one go. And like the first five can be a text, the next five can be an image then again a text than video, and so on. And it is super easy to access them as well. Also, you can edit them quite easily as well. It's not that hard like the Lisp used to be in the past. And supermarket has a mix blend of the database. And modern databases like Data Lake can be very useful, undoubtedly.

You can store security type of requirements, like CCTV footage, each shop details like shop ID, Product list, shop type, electricity bill, hours of opening, floor, facilities, no. of employees, etc., and like this, we can have the details for the entire supermarket, and each shop there definitely. And we can perform various actions on behalf of each shop and market as well. The database can hence be very useful definitely

Explanation:

Please check the answer.

8 0

3 years ago

Letter Frequency Write a function that will take a string and return a count of each letter in the string. For example, "my dog

Nostrana [21]

Answer:

Check the explanation

Explanation:

Code to copy:

// ConsoleApplication7.cpp : Defines the entry point for the console application.

//

#include "stdafx.h"

#include <iostream>

#include <cstring>

#include <string>

using namespace std;

int * letterFrequency(char s[]);

int main()

{

int *freq_letters;

char *s = new char[100];

freq_letters = new int[26];

//To read the input string in order to find the frequency of each letter

cout << "Enter a string: ";

cin.getline(s, ' ');

//call the function to find the occurrence of each alphabet

freq_letters = letterFrequency(s);

//Display the count

cout << "Letter Frequency " << endl;

for (int i = 0; i < 26; i++)

{

//Constriant to check if the letter appeared at least once in the string and so printing the frequency of its occurence

if (freq_letters[i] != 0)

cout << " " << static_cast<char>(i + 'a') << " " << freq_letters[i] << endl;

}

system("pause");

return 0;

}

//Define the function to find occurrence of each letter in the input string

int * letterFrequency(char s[])

{

int *occurrence_array;

//to store the output of occurrences for each alphabet

occurrence_array = new int[26];

// to store the count of occurrence for each letter temporarily

int letter_count;

// for loop to check the occurrence for all 26 alphabets

for (int i = 0; i < 26; i++)

{

letter_count = 0;

for (int j = 0; j < strlen(s); j++)

{

/*comparing the ascii values of each alphabet with every character from the string by converting it to lower case i.e. case insensitive*/

if (int('a') + i == int(tolower(s[j])))

letter_count++;

}

occurrence_array[i] = letter_count;//To store the count calculated for each alphabet

}

return occurrence_array;

}

The following below code screenshot and output shows that when the string is entered, the output will shows each lettercount irrespective of whether the letter is in capitals or small and does not count non-letter characters (i.e spaces, punctuations etc.)