Answer:
def countdown(n):
if n <= 0:
print('Blastoff!')
else:
print(n)
countdown(n-1)
def countup(n):
if n >= 0:
print('Blastoff!')
else:
print(n)
countup(n+1)
number = int(input("Enter a number: "))
if number >= 0:
countdown(number)
elif number < 0:
countup(number)
<u>Outputs:</u>
Enter a number: 3
3
2
1
Blastoff!
Enter a number: -3
-3
-2
-1
Blastoff!
Enter a number: 0
Blastoff!
For the input of zero, the countdown function is called.
Explanation:
Copy the countdown function
Create a function called countup that takes one parameter, n. The function counts up from n to 0. It will print the numbers from n to -1 and when it reaches 0, it will print "Blastoff!".
Ask the user to enter a number
Check if the number is greater than or equal to 0. If it is, call the countdown function. Otherwise, call the countup function.
Answer and Explanation:
def loop(start, stop, step):
return_string = ""
if step == 0:
step = 1
if start > stop: # the bug was here, fixed it
step = abs(step) * -1
else:
step = abs(step)
for count in range(start, stop, step):
return_string += str(count) + " "
return return_string.strip()
<span>buffer is what your looking for my friend made this it should help https://quizlet.com/20507517/ch-4-operating-systems-and-file-management-flash-cards/</span>
Answer:
Please check the attachment.
Explanation:
avg turnaround time = (38+7+42+33+18)/5= 27.6
avg waiting timee = (33+5+28+23+17)/5= 21.2
And its D, A C in Gantt chart at last and exit time are 33, 38 and 42 mentioned as last three in Gantt chart.
