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alexdok [17]
3 years ago
10

Ella's college professors assign homework independently from each other. ella knows that there is a 60% chance that she will hav

e math homework tonight and a 70% chance that she will have english homework. what is the probability that she will not have math or english homework tonight? 10% 12% 42% 70%
Mathematics
2 answers:
Katena32 [7]3 years ago
7 0
To answer this question, you will multiply the chance of NOT having english homework (100-70=30% chance) by the chance of her NOT having math homework (100-60=40%).

This would be 0.3 x 0.4=0.12 or 12% chance of both occurring.
LekaFEV [45]3 years ago
5 0

Answer:

B. 12%  

Step-by-step explanation:

We have been given that Ella knows that there is a 60% chance that she will have math homework tonight and a 70% chance that she will have English homework.

Since we know that probability of not happening an event can be found by subtracting probability of happening the event from 1.

\text{P(No math homework tonight)}=1-0.6=0.4

\text{P(No English homework tonight)}=1-0.7=0.3

Since both events are independent so we will multiply probability of no math homework tonight by probability of no English homework to find no math or English homework tonight.

\text{P(No math or English homework tonight)}=0.4\times 0.3

\text{P(No math or English homework tonight)}=0.12

Converting 0.12 to percent we will get,

0.12\times 100=12\%

Therefore, the probability that Ella will not have math or English homework tonight is 12%.

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