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3 years ago

Find the perimeter of a regular octagon if one side has a measure of 8cm A) 16 cm B) 56cm C) 64cm D) 72cm

Mathematics

2 answers:

zysi [14]3 years ago

8 0

C. 64cm
Hope this helps! :)

Vesna [10]3 years ago

5 0

C. 64cm. P=8a=8·8=64. I hope this helps you.

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Ne4ueva [31]

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Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each

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3 years ago

Lisa drove 7,000 miles in 70 days. She drove the same number of miles each day.

inysia [295]

Answer: I'd assume its B 100 miles each day.

Step-by-step explanation:

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3 years ago

Read 2 more answers

An insect crawls 30 inches in 16.3 minutes. If

omeli [17]

Answer:

Step-by-step explanation:

Convert 6 hours to minutes so that 6 hours and 16. 3 minutes can be in the same units.

Since 1 hour = 60 minutes, then 6 hours = 6 x 60 minutes = 360 minutes

Since the insect has more minutes to crawl (360 minutes), then we expect more inches to be covered. Therefore, the ratio is 360 minutes to 16.3 minutes

= 360 minutes : 16.3 minutes

= 360 : 16.3

Now express the ratio as fraction and relate it with 30 inches

= 360/16.3 x 30/1

= 10800/16.3

= 662 .576687 and this is approximately 650 inches

Answer = 650 = (C)

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2 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago