I take it we aren't solving for x.
So
2x + 28 + 9 - 5
2x + 28 + 4
2x + 32.
Answer:
<em>1, 2, 3, 6</em>
Step-by-step explanation:
The given equation is,
We need to to find all the whole values of a for which the solution of the equation i.e x will be a whole number.
We know that when a number is divided by one of its factor it leaves a remainder of 0 or the result we get is a whole number.
That is why, we need a as one of the factors of 6, i.e 1, 2, 3, 6 in order to get x as a whole number.
Answer:
Step-by-step explanation:
0.144 rational
√(0.144) irrational
√(0.0144)=0.12 rational
Complete question :
Cheddar Cheese
$3/lb
Swiss Cheese
$5/lb
Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Answer:
10 lbs of cheddar cheese
6 lbs of Swiss cheese
$3a + $5b = $30
Step-by-step explanation:
Given that :
Cheddar cheese = $3/lb
Swiss cheese = $5/lb
Total amount budgeted for cheese = $30
How many pounds of cheese can Keisha get if she buys only Cheddar cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of cheddar cheese
$30 / 3 = 10 pounds of cheedar cheese
Only Swiss cheese?
Pounds of cheedar cheese obtainable with $30
Total budget / cost per pound of Swiss cheese
$30 / 5 = 6 pounds of Swiss cheese
A mixture of both cheeses?
What linear equation in standard form can she use to model the situation?
Let amount of cheddar cheese she can get = a
Let amount of Swiss cheese she can get = b
Hence,
(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount
(3 * a) + (5 * b) = $30
$3a + $5b = $30