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3 years ago

What is the area of the parallelogram below? Use the formula a=bh

Mathematics

1 answer:

Nana76 [90]3 years ago

6 0

Where where is the formula you didn't even post a picture?

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How can a baseball team win a game without a single man crossing home plate

Yanka [14]

A women's team, or children's team. The other team forfeits. Having a married man cross the plate (only if your teacher has a sense of humor)

3 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

3 years ago

Find the volume of this figure. Round your answer to the nearest hundredth, if necessary.

solmaris [256]

Answer:

V = 3617.28 m^3

Step-by-step explanation:

Volume of a cone

V = 1/3 πr^2h

Where r = 24/2 = 12 m

h = 24 m

Plug in

V = 1/3 (3.14) (12^2)(24)

V = 3617.28 m^3

5 0

3 years ago

Multiply. Express your answer in simplest form. 3 3/4 × 2 2/9

Sergio [31]

Answer:

The answer is 8 1/3.

3 0

3 years ago

Read 2 more answers

Help me please,Thanks

alukav5142 [94]

I have not done measurements in a really long time and i am most likely wrong but i think its 45

8 0

4 years ago