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3 years ago

Please answer it now in two minutes

Mathematics

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

3.6

Step-by-step explanation:

Pythagorean theorem:

a^2 + b^2 = c^2

(6 km)^2 + b^2 = (7 km)^2

36 + b^2 = 49

b^2 = 13

b = sqrt(13)

b = 3.6

Answer: 3.6 km

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Rita's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $55 a day for fo

MArishka [77]

"The company pays $55 a day for food and lodging and $0.45 for each mile traveled" means that if she travels m miles and is on a trip for x days then Rita will receive:

55x + 0.45m dollars.

Rita drove 300 miles, means that m=300. Thus 55x + 0.45m becomes 

 $55x+0.45m=55x+0.45 \cdot 300=55x+135$ (dollars.)

She was reimbursed $2,335 means that $55x+135=2,335$ .

Part A: $55x+135=2,335$ .

Part B:

We are given the equation 55x+135=2,335. Subtracting 135 from both sides we have:

55x=2,335-135=2,200.

Dividing both sides by 55, we get: x=2,200/55=40.

Part C: since x represents the number of days Rita spend on this trip, and x=40, then Rita spent 40 days on this trip.

5 0

3 years ago

Will mark as brainliest if correct

Dvinal [7]

5= 7 ^x
X=ln5/ln7
X=0.827

5 0

3 years ago

May someone help me with these 2 again

cestrela7 [59]

Answer:

1. 180

2. x = 31

Step-by-step explanation:

1. the sum of the interior angles of every triangle is always 180

2. using what we know from problem 1, we can create an equation:

x + 10 + 2x - 5 + 2x + 20 = 180

add like terms: 5x + 25 = 180

subtract 25 from both sides: 5x = 155

divide both sides by 5: x = 31

3 0

2 years ago

Determine which function has the greatest rate of change over the interval [0, 2].

ruslelena [56]

Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: $m= \frac{y_{2}-y_{1}}{x_2-x_1}$

Rate of change of $a$ :
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of $a$ :
$m= \frac{y_{2}-y_{1}}{x_2-x_1}$
$m= \frac{4-1}{2-0}$
$m= \frac{3}{2}$
$m=1.5$
The average rate of change of the function $a$ over the interval [0,2] is 1.5

Rate of change of $b$ :
Here the end points are (0,0) and (2,2)
$m= \frac{2-0}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $b$ over the interval [0,2] is 1

Rate of change of $c$ :
Here the end points are (0,-1) and (2,0)
$m= \frac{0-(-1)}{2-0}$
$m= \frac{1}{2}$
$m=0.5$
The average rate of change of the function $c$ over the interval [0,2] is 0.5

Rate of change of $d$ :
Here the end points are (0,0.5) and (2,2.5)
$m= \frac{2.5-0.5}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $d$ over the interval [0,2] is 1

We can conclude that the function that has the greatest rate of change over the interval [0, 2] is the function a.

4 0

3 years ago

The legs of the right triangle have Links of 28 metres and 21 metres

GarryVolchara [31]

If we're trying to find the hypotenuse we'll take the $\sqrt{28^{2}+ 21^{2} }$
Getting 35.

35

4 0

3 years ago