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3 years ago

2x/x-3 - 6/x-3 . I need a step by step explanation , please

Mathematics

1 answer:

Harman [31]3 years ago

8 0

When adding/subtracting fractions you need a common denominator, but you already have one, which is x-3. So in general:

a/c-b/c=(a-b)/c so you just have:

(2x-6)/(x-3) now if you factor 2 from the numerator

2(x-3)/(x-3) the (x-3)s cancel out leaving

2

However! Note that division by zero is undefined, so x cannot equal 3. (because both original fractions had denominators of x-3)

What this all means is that that expression will equal 2 for all real values of x other than 3.

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Could someone please help me. Thanks!!! 12 points!

Svetlanka [38]

The horizontal beams are what I like to think of as "rail road tracks". The metal portion of the tracks anyway. Notice how angle 2 and angle 8 are inside the tracks, so we consider them "interior angles"

Furthermore, they are on opposite or alternate sides of the transversal line. The transversal line is the non-parallel line that cuts through the "rail road tracks".

Put those two facts together and we get "alternate interior angles" as our final answer

8 0

3 years ago

What is the value of (0.5)^4 in a fraction

kicyunya [14]

Answer:

12.5%

Step-by-step explanation:

hope it helps!!!

6 0

3 years ago

Read 2 more answers

What is 2x3 - 5x2 - 4x - 25<br> divided by X - 4

Nonamiya [84]

Answer:

2x² + 3x + 8 + 7/x-4

Step-by-step explanation:

For this problem, we can use synthetic division.

4 | 2 -5 -4 -25

| 8 12 32

|_________

2 3 8 7/x-4

This means the quotient is 2x² + 3x + 8 + 7/x-4.

7 0

3 years ago

The difference between the roots of the quadratic equation x^2−14x+q=0 is 6. Find q.

pychu [463]

Answer :

The value of q for, the given quadratic equation is 40

Step-by-step explanation :

Given quadratic equation as :

x² - 14 x + q = 0

And , Difference between the roots of equation is 6

Let A , B be the roots of the equation

So, A - B = 6

The roots of the quadratic equation ax² + bx + c = 0 as can be find as :

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

x = $\frac{14\pm \sqrt{(-14)^{2}-4\times 1\times q}}{2\times 1}$

or, x = $\frac{-14\pm \sqrt{196-4 q}}{2}$

Or, x = $\frac{-14\pm \sqrt{196-4 q}}{2}$

So , The roots are

A = $-7 + \frac{\sqrt{196-4q}}{2}$

And B = $-7 - \frac{\sqrt{196-4q}}{2}$

∵ The difference between the roots is 6

So, A - B = 6

Or, ( $-7 + \frac{\sqrt{196-4q}}{2}$ ) - ( $-7 - \frac{\sqrt{196-4q}}{2}$ ) = 6

Or, ( - 7 + 7 ) + 2 ( $\sqrt{196-4q}$ = 6

Or, 0 + 2 ( $\sqrt{196-4q}$ = 6

∴ 196 - 4 q = 36

or, 4 q = 196 - 36

or 4 q = 160

∴ q = $\frac{160}{4}$

I.e q = 40

S0, The value of q = 40

Hence The value of q for, the given quadratic equation is 40 . Answer

8 0

3 years ago

Marley was asked to solve x2 - 4x + 9 = 0 using the Quadratic Formula. She found the discriminant first and decided she did not

saveliy_v [14]

We have been given Marley was asked to solve $x^2-4x+9 = 0$ using the Quadratic Formula. She found the discriminant first and decided she did not need to continue with the Quadratic Formula.