To solve this, we need to know how to find the mean of a set of data and how to find the median of a set of data.
To find the mean, or often called the average, we should add all of the values up, and then divide it by the number of values.
588+838+691+818+846+725+605+732+750 = 6593
6593/9=732.556
The problem tells us we should round to the nearest point, so our mean credit score is 733.
To find the median, we need to order the data from lowest to highest and find out which credit score(s) are right in the middle. If there are 2 in the middle, we simply should add them and divide by 2 to get our median. An easy way to do this is after you order them, you simply cross off one on each side until there is only 1 (or 2) left.
588 605 691 725 732 750 818 838 846
605 691 725 732 750 818 838
691 725 732 750 818
725 732 750
732
Since we only have one number in the middle, we are done with the median! We know our median is 732.
Now we simply need to compare them and subtract the lower one from the higher one.
Mean:733
Median: 732
733>732
We know the mean is bigger, so we should subtract the median from the mean.
733=732=1
Using the logic above, we can see that the mean is 1 point higher than the median.
Answer:the asnwer is d
Step-by-step explanation:
Answer:
. (In this problem we prove a fact that you demonstrated experimentally in Problem1 of the fourth assignment.) LetABCDbe a quadrilateral. LetM, N, P,andQbe the midpoints of the sides. Prove the area ofMNPQis one half the area ofABCD.4. (See Figure 1.) Give the proof of Theorem 24 for Case (iii). Given:MandNarethe midpoints ofABandAC,MX⊥AB,NX⊥AC, andXis onBC. To prove:Xis on the perpendicular bisector ofBC.XNCMABFigure 1
5. (See Figure 2). Prove Case (ii) of Theorem 28. Given:A0,B0andC0are collinear.To prove:A0BA0CB0CB0AC0AC0B= 1.C'A'B'ABCFigure 26. (See Figure 3.)Given:6A=6B,AD=BE,6ADG=6BEF.To prove:6CFE=6CGD.FGECDBAFigure 37. Suppose that you have a computer program which can perform the following func-tions:
(a) It can draw points, and draw line segments connecting two points.(b) Given a pointOand a line segmentAB, it can construct the circle with centerOand radius equal to the length ofAB.(c) Given a line segmentAB, it can find the midpoint.(d) Given a lineland a pointP(not necessarily lying onl), it can construct theline throughP
Step-by-step explanation:
Answer: 59 & 21
Step-by-step explanation:
so this probably won't be the best explanation, but here goes:
For the sake of knowing the two numbers aren't equal to each other, I decided to do variables n and x, so:
n+x=80
Now we need to find the value of n:
So the question sets this up as
n-2x=17. We need to change the equation so that we're solving for n, so: n=17+2x
Next we need to solve n+x=80, to do that we need to make it into x=80-n
Now that they're set up like this we can do : 80-n=17+2x.
I honestly don't know how to explain it the rest of the way but if you plug in those two numbers they should be right.