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First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)
nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165
This will be used in the formula below
Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624
The final answer here is choice C) -624
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M=153.46w, L=128.90+127.68w they will be equal when M=L so
153.46w=128.90+127.68w subtract 127.68 from both sides...
25.78w=128.90 divide both sides by 25.78
w=5
So after five weeks they have deposited the same amount of money.
Each of them has deposited <span>$153.46*5=$767.30, so the account has twice that amount.
Thus the total amount in the account is 767.30*2=$1534.60</span>
Answer:
A. the proper steps that should have been taking would be to first would be to raise 2 to the power of 3, which would give you 8. Then raise it to the power of 1. So the most likely error is C. they added the exponents.