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blagie [28]
3 years ago
10

Math question Informatin in dot plots

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Range =  difference between the highest and the lowest

Mode = Data that occurs the most time

Median = Arrange  the data in ascending order. The middle data is the median. If number of data is even, median is the average of the two middle  terms.

1) Range = 28 -21 = 7

Mode = 25

Number of data (Count the total dots) = 14

Median = average of  7th and 8th term

Median = (25+25)/2 = 50/2 = 25

2) Range = 0.18 - 0.11 = 0.07

Mode = 0.15 and 0.16

Number of data = 23

Median =12th term = 0.15

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3/12 or simplified 1/4

Step-by-step explanation:

First make the denominators the same. We can make 12 the common denominator. To make 3/4 have a denominator do the following:

Multiply the numerator and denominator by 3 since 4x3=12. The new number becomes 9/12.

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Step-by-step explanation:

how do you solve 135x42? (step by step please)

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3 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
3 years ago
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