Answer:
To be greater than 20, we can either use values of 2 through 9 for the first digit, which is a total of 8 digits. For the second digit, in order to be even, we can use 1, 3, 5, 7, or 9. ( 5 options). Multiply together and we have the total number of possibilities.
Each half-life reduces a sample by one half.
So after 1 half-life there is 1/2 left
2 half-lives 1/4
3 half-lives 1/8
4 half-lives 1/16
5 half-lives 1/32
There would be (1/32) of 120 remaining.
or 3.75 grams.
Source:
http://www.1728.org/halflife.htm
Answer:
Step-by-step explanation:
Given that you have been discussing a research project with your friend Connor. Connor has told you that his research hypothesis states, the mean of population 1 is not equal to the mean of population 2.
So our null hypothesis should be
This is a two tailed test
How we write in symbols is shown in Ha as above.
not equal to sign is used here to represent.
Problem 16
<h3>Answer: i</h3>
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Work Shown:
The exponent 41 divided by 4 leads to
41/4 = 10 remainder 1
The "remainder 1" means that
i^(41) = i^1 = i
The reason why I divided by 4 is because the pattern shown below
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
repeats itself over and over. So this is a block of four items repeated forever.
=====================================
Problem 18
<h3>Answer: 1</h3>
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Work Shown:
Divide 3136 over 4 to get
3136/4 = 784 remainder 0
Therefore,
i^3136 = i^0 = 1
=====================================
Problem 20
<h3>Answer: i</h3>
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Work Shown:
Combine i^6*i^7 into i^13. We add the exponents here
Now divide by 4 to find the remainder
13/4 = 3 remainder 1
So, i^13 = i^1 = i
Answer:
1,2,4,5,10,20
Step-by-step explanation:
1*20
2*10
4*5
These are the factors of 20
