Answer:
W = kq1q2 / r
Step-by-step explanation:
W varies jointly as the product of q1 and q2 and inversely as radius r
Product of q1 and q2 = q1q2
W = (k*q1"q2) / r
W = kq1q2 / r
Where,
W = work
q1 = particle 1
q2 = particle 2
r = radius
k = constant of proportionality
The answer is W = kq1q2 / r
It would be 2u3+4u2-2u-4u2-8u+4= 2u3-10u+4
Exponential probability distribution f(r) = Ae-r/ λ λ where A = a constant, λ λ = mean free path 3. The attempt at a solution P = Integral (limits λ λ to ∞ ∞ )f(r) dr / Integral (limits 0 to ∞ ∞ ) f(r) dr
2(x)^2 - 2(x) - 12 = ?
2(x)^2 - 2(x) - 12
(x)^2 - 6 - x
Multiply ↪1 (-6) = -6
1 + -6 = -5 , right?
-3 + 2 = -1, right?
After we have pulled out the like terms we have to add/subtract! x(x) - 3
Search for the common denominator
2(x) - 3
You can add up 4 for your terms
x + 2 (x - 3)
Make sure you solve this↪ 2 = 0
x + 2 = ?
x + 2 = 0
We have found the first; x = -2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Since, this one has a single variable, I'll make the step easier and quicker
Solve this part ↪ x-3 = 0
If we had the number 3 to your sides we would have found the outcome of the next x
So, the second x is 3
So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)
Answer:
7:35
Step-by-step explanation:
we take the 35 and 45 and add it together, then take out the 60 minutes and put that in as an hour. the practice is two hours long plus the hour we took out. then the remaining minutes are 20. we add 20 minutes and three hours
