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max2010maxim [7]
3 years ago
7

PLEASE HELP!! WORTH 70 POINTS!!!!!!!!! The box plot was created by using which pieces of data? A box-and-whisker plot. The numbe

r line goes from 0 to 130. The whiskers range from 5 to 130, and the box ranges from 10 to 105. A line divides the box at 40. a maximum of 130 and a lower quartile of 10 a maximum of 130 and a lower quartile of 5 a maximum of 135 and a lower quartile of 10 a maximum of 135 and a lower quartile of 5
Mathematics
2 answers:
ddd [48]3 years ago
5 0

Answer:

its worth 5 not 70

Step-by-step explanation:

Softa [21]3 years ago
3 0

Answer:

The Answer is A.

Step-by-step explanation:

I just took the test. ༼ つ ◕_◕ ༽つ

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Answer:

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Step-by-step explanation:

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Answer:

1/6

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Select True or False for each statement.
mote1985 [20]
<h2>Answer:</h2>

For a real number a, a + 0 = a.  TRUE

For a real number a, a + (-a) = 1.  FALSE

For a real numbers a and b, | a - b | = | b - a |.  TRUE

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

<h2>Explanation:</h2>

  • <u>For a real number a, a + 0 = a.  </u><u>TRUE</u>

This comes from the identity property for addition that tells us that<em> zero added to any number is the number itself. </em>So the number in this case is a, so it is true that:

a+0=a

  • For a real number a, a + (-a) = 1.  FALSE

This is false, because:

a+(-a)=a-a=0

For any number a there exists a number -a such that a+(-a)=0

  • For a real numbers a and b, | a - b | = | b - a |.  TRUE

This is a property of absolute value. The absolute value means remove the negative for the number, so it is true that:

\mid a-b \mid= \mid b-a \mid

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This is false. By using distributive property we get that:

(a + b)(a + c)=a^2+ac+ab+bc \\ \\ a^2+ab+ac+bc \neq a+(b.c)

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A rational number is a number made by two integers and written in the form:

\frac{u}{v} \\ \\ v \neq 0

Given that a \ and \ b are rational, then the result of dividing them is also a rational number.

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3 years ago
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