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Fiesta28 [93]
3 years ago
6

What is 12.4 less then the sum of 19.23 and 10.02?

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0
So sum means the answer to a addition problem and less means subtract. 
(19.23+10.02)-12.4= ?
29.25-12.4= 16.85

Hope this helps! If you have any questions, just ask!
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Which of the following expressions is equivalent to a perfect square?
Liula [17]

Answer:

F

Step-by-step explanation:

if you do the math you end up with 49 which is a perfect square of 7

3 0
2 years ago
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

8 0
2 years ago
A number subtracted from 90 is three times that number
sergeinik [125]
90-n=3n
90=4n
22.5=n

Final answer 22.5
3 0
3 years ago
Read 2 more answers
Please help me its do tomorrow
PolarNik [594]
2x+3 + 3x-4 + 2x+3 + 3x-4 = 78
10x -2 = 78
10x = 80
x=8

deck is 2(8)+3 by 3(8)-4, or 19 by 20
3 0
3 years ago
The sum of two integers with different signs is 8. Give two possible intergers that fit this description
choli [55]
10+ (-2)= 8 9+(-1)=8
5 0
3 years ago
Read 2 more answers
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