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ladessa [460]
3 years ago
10

HELP PLS GIVING BRAINLIEST

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

y = mx+b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

(0,1)\\(1, -2)

We found the slope:

m = \frac {y2-y1} {x2-x1}\\m = \frac {-2-1} {1-0} = \frac {-3} {1} = - 3

So, the equation is of the form:

y = -3x + b

We substitute a point to find "b":

1 = -3 (0) + b\\1 = b

Finally, the equation is:

y = -3x+1

Answer:

Option C

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Step-by-step explanation:

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Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

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c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

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We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

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