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Lorico [155]
3 years ago
7

I need help finding out the domains and range of this function

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

i believe that the domain,x, is 0≤x≤∞

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Find the sum of the least and greatest two digit prime numbers whose digits are also prime?
adoni [48]
First, we need to know the smallest two digit prime number. It can't start with one, since one is not prime, so it must start with two (or be in the twenties.) 20 is divisible by 2, 4, 5, and 10, 21 is divisible by 7 and 3, 22 is divisible by 2 and 11, so the smallest prime number is 23.

Now we need the largest two-digit prime number. It cannot start with nine or eight, since both are composite, so it must start with seven (be in the seventies.) 79 is the largest integer in the seventies and also happens to be prime, so there's our largest two digit prime number.

now we just need to add them for the sum:
23+79=102

hope I helped, and let me know if you have any questions :D
7 0
3 years ago
If r=10 and s=31 find R. Round to the nearest tenth
Vsevolod [243]

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "R":

 \alpha =arctan(\frac{opposite}{adjacent})

You know that you need to find the measure of "R" and r=10 (which is the opposite side) and s=31 (which is the adjacent side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get:

R=arctan(\frac{10}{31})\\\\R=17.9\°

3 0
3 years ago
Read 2 more answers
Kim ate 3/10 of a bag of chips, sandy ate 3/7 of a bag, and jeff ate 3/9 of a bag. who ate the most
aksik [14]

Answer:

sandy

Step-by-step explanation:

3/10 = .3

3/7=.43

3/9=.333333

sandy then jeff then kim

6 0
2 years ago
Read 2 more answers
Please help! thanks!
9966 [12]
Yes, it is.
2(3) - 3(2) = 0
2(3) + 2 = 8
6 0
2 years ago
The 19 members of a football team are trying to raise at least $1266.00 to cover the traveling cost for a holiday tournament. If
SIZIF [17.4K]
To solve this, you need to do 1,266-451. that equals 815. then, divide 815 by 19. you should get 43. hope that helps.
8 0
3 years ago
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