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4 years ago

HELP PLEASE AND SHOW WORK AS WELL

1 answer:

3 0

1) 2(x - 5) = 6x - (x - 8)

On the left side of the equal sign, multiply everything in the parenthesis by 2.
On the right side of the equal sign, multiply everything in the parenthesis by -1.

2x - 10 = 6x - x + 8

Combine like terms.

2x - 10 = 5x + 8

Add 10 to both sides.

2x = 5x + 18

Subtract 5x from both sides.

-3x = 18

Divide -3 on both sides.

x = -6

2) 8x - 2y = 4z

Subtract 8x from both sides.

-2y = 4z - 8x

Divide -2 on both sides.

y = 4z - 8x / -2

Hope this helps!

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A gas company’s delivery truck has a cylindrical tank that is 16 feet in diameter and 48 feet long. How much gas can fit in the

Nady [450]

Answer: V=9651 ft^3

Explanation: This is a volume question and the formula for volume of a cylinder is πr^2h.

The radius is the diameter divided by 2, which is 8.

We can put the equation in terms of π by doing π*(8^2*48)=3072π.

Solving this gives us about 9650.972632, which you can round to get 9651.

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3 years ago

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Gemiola [76]

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3 years ago

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The median age of residents of the United States is 31 years. If a survey of 100 randomly selected U.S. residents is to be taken

makvit [3.9K]

Answer:

P (x≥ 57) = 6.7789 e^-8

Step-by-step explanation:

Here n= 100

p = 31/100 = 0.31

We formulate the null hypothesis that H0: p= 0.31 against the claim Ha: p≠0.31

The significance level is chosen to be ∝= 0.05

The test statistic x to be used is X, the number U.S. residents is to be taken which is at least 57

The binomial calculator gives the

P (x≥ 57) = 6.7789 e^-8

IF ∝= 0.05 then ∝/2 = 0.025

We observe that P (x≥ 57) is less than 0.025

Hence we reject H0 and conclude that p ≠0.31

This is true because for normal distribution the median = mean which is usually the 50 % of the data.

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3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

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4 years ago

PLEASE HELP FAST ITS MULTIPLE CHOICE!

loris [4]

Answer: It's A

Step-by-step explanation: X + Y is the total books, which should equal 8. Some books treat them as X, while the rest treat them as Y. You end up with 12x+18y=108.

6 0

3 years ago