Answer:
C
Step-by-step explanation:
Given 2 secants intersect a circle from a point outside the circle, then
The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is
x(x + 10 + x) = 6(6 + 10 + x)
x(2x + 10) = 6(16 + x) ← distribute parenthesis on both sides
2x² + 10x = 96 + 6x ← subtract 96 + 6x from both sides
2x² + 4x - 96 = 0 ← in standard form
Divide through by 2
x² + 2x - 48 = 0 ← factor the left side
(x + 8)(x - 6) = 0
Equate each factor to zero and solve for x
x + 8 = 0 ⇒ x = - 8
x - 6 = 0 ⇒ x = 6
However x > 0 ⇒ x = 6 → C
I was on the right track, lol. 280.5 miles.
Answer:
<u>option (2) it is and isosceles triangle. </u>
Step-by-step explanation:
In circle L, points E and F lie on the circle such that E, F and L are not collinear
If LE, LF and EF are drawn
So, LE = EF = the radius of the circle L
So, LEF is an isosceles triangle.
The answer is option (2) it is and isosceles triangle.
