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2 years ago

How do I solve this? i missed ONE class

Mathematics

2 answers:

lisov135 [29]2 years ago

6 0

Answer:

a < 42

Step-by-step explanation:

Question : 4a + 9a - 6a < 42

Answer :

4a + 9a - 6a < 42

Combine like terms.

13a - 6a < 42

7a < 42

Divide both sides by 7.

a < 42

Hope this helps you :-)

Let me know if you have any other questions :-)

luda_lava [24]2 years ago

6 0

Answer:

$\large\boxed{\boxed{\underline{\underline{\maltese{\pink{\pmb{\sf{\: Solution :- \: a \: < \: 6 }}}}}}}}$

Step-by-step explanation:

We need to solve the below given inequality $\downarrow$

4a + 9a - 6a < 42

For this, we need to combine all the like terms at first. So

4a + 9a - 6a < 42

13a - 6a < 42

7a < 42

We know that, 42 is divisible by 7. So, let's divide both the sides of the inequality by 7.

7a < 42

a < 42/7

<u>a < 6</u>

_________

Hope it helps!

Check out more helpful links here:

■ brainly.com/question/17448505

■ brainly.com/question/15816805

$\mathfrak{Lucazz}$

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Given triangle abc with vertices A(2,-1), B(5,6), C(-1,4) as shown. Find the number of square units in the area of triangle abs

Roman55 [17]

Answer:

The area of the triangle is 18 square units.

Step-by-step explanation:

First, we determine the lengths of segments AB, BC and AC by Pythagorean Theorem:

$AB = \sqrt{(5-2)^{2}+[6-(-1)]^{2}}$

$AB \approx 7.616$

$BC = \sqrt{(-1-5)^{2}+(4-6)^{2}}$

$BC \approx 6.325$

$AC = \sqrt{(-1-2)^{2}+[4-(-1)]^{2}}$

$AC \approx 5.831$

Now we determine the area of the triangle by Heron's formula:

$A = \sqrt{s\cdot (s-AB)\cdot (s-BC)\cdot (s-AC)}$ (1)

$s = \frac{AB+BC + AC}{2}$ (2)

Where:

$A$ - Area of the triangle.

$s$ - Semiparameter.

If we know that $AB \approx 7.616$ , $BC \approx 6.325$ and $AC \approx 5.831$ , then the area of the triangle is:

$s \approx 9.886$

$A = 18$

The area of the triangle is 18 square units.

7 0

3 years ago

What is the digit in 913 and where's the digit in the tens place and the value of the digit tens someone answer for my homework

lorasvet [3.4K]

4. Period with the digits 913 is called thousands period.
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Hope it will help you :)

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3 years ago

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jekas [21]

Put the values of the variables in place of the variables in the expression, then do the arithmetic.

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Answer:

Step-by-step explanation:

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2 years ago

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Margaret [11]

Let's check.

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Answer: TRUE

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3 years ago