Answer:
3
Step-by-step explanation:
Given the data: 7 6 5 9 3 4 7 9 5 8
INTERQUARTILE RANGE (IQR) = Q3 - Q1
Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9
Q3 = 0.75(n+1)th term
Q3 = 0.75(10 + 1) th term
Q3 = 0.75(11)th term = 8.25th term
Taking the 8th term = 8
Q1 = 0.25(11)th term = 2.75th
Taking the average of the 8th and 9th term:
(5 + 5) / 2 = 10/2 = 5
Q3 - Q1 = (8 - 5) = 3
Answer:
x = 29/8c
Step-by-step explanation:
2/3(cx+1/2) - 1/4+ 1/4 = 5/2+1/4
2/3(cx+1/2) = 11/4
1/3(cx+1/2) = 11/4 / 2
cx/3 + 1/2/3 = 11/4/2
cx/3 + 1/2*3 = 11/4/2
cx/3 + 1/6 = 11/4/2
cx/3 + 1/6 = 11/4*2
cx/3 + 1/6 = 11/8
cx/3 = 11/8 - 1/6
cx/3 = 29/24
cx = 29/24 * 3
x = 29/8 / c
x = 29/8c
Answer:
Step-by-step explanation:
Given:
The equation of the known line is:
A point on the unknown line is (-4, 4)
Now, since the two lines are parallel, their slopes must be equal.
Now, slope of the known line is the coefficient of 'x' which is 
.
Therefore, the slope of the unknown line is also 
Now, for a line with slope 'm' and a point on it 
is given as:
Here, 
. Therefore,
Hence, the equation of the unknown line is .
To generate the equation we set up the factors
(x+3) * (x-1) * (x-2) which equals
x^2 + 2x -3 * (x-2)
x^3 +2x^2 -3x -2x^2 -4x +6 equals
x^3 -3x -4x +6 which equals
x^3 -7x +6
