The point on the line, -1/3, shows the opposite of 1/3, or the opposite of the opposite of -1/3
Answer:
Point P = 14.32
Step-by-step explanation:
Point P represents the distance from point A to point B.
The formula is given as:
x1 = 0, y1 = 3, x2 = 6, and y2 = -10
P ≅ 14.32
Answer:
x= 1
y= -3
Step-by-step explanation:
multiply them to get common factor for y or x:
3(7y+10x=-11)
10(4y-3x=-15)
21y+30x=-33
40y-30x=-150 <em>x's cancel out so solve for y</em>
61y = -183
/61 /61
y = -3 <em> insert y into either equation and solve for x</em>
<em />
<em>4(-3) -3x=-15</em>
<em>x = 1</em>
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
See picture and explanation below.
Step-by-step explanation:
With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.
A is defined as denotes the vector of coordinates of respect to the basis (we can apply this definition because forms a basis for the domain of T).
The vector of coordinates can be computed in the following way: if then .
Note that we have all the required information: then
hence
The matrix A is on the picture attached, with the multiplication A(1,1,1).
Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:
In this last case, we can either use the linearity of T or multiply by A.