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igor_vitrenko [27]
3 years ago
7

Kara has a cube with side lengths of 4.2 cm. Which is the best estimate of the volume of the cube?

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
Side of the cube = 4.2 cm
Estimating it to nearest ones = 4 cm

So, Its volume= s³ = (4)³= 64 cm³
Iteru [2.4K]3 years ago
4 0

Answer:  D) 64 cm³

Step-by-step explanation: side of cube= 4.2 cm which can be approximated as 4 cm

volume of cube= side³

                          =4³

                           =64 cm³

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Write an equation in slope-intercept form of the line shown.
MatroZZZ [7]

Answer:

y = 5/3x + 20/3

Step-by-step explanation:

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Slope:

m=(y2-y1)/(x2-x1)

m=(-5-0)/(1-4)

m=(-5)/(-3)

m=5/3

Slope-intercept:

y - y1 = m(x - x1)

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3 0
3 years ago
Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14
PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_{0}e^{-\lambda t}

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_{0}e^{-0.00012097\cdot t}

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_{0}e^{-0.00012097\cdot t}

Simplifying:

0.10=e^{-0.00012097\cdot t}

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=\frac{log 0.10}{-0.00012097}

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0
3 years ago
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gayaneshka [121]

Answer:

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Step-by-step explanation:

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Yo sup??

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