Question

Eight more than twice a number increased by 3 is equal to 79. Find the number

Answer 1

translate, call the number, n

Eight more than (8+) twice a number increased by 3 (2(n+3)) is equal to (=) 79 (79)

8+2(n+3)=79

minus 8 both sides

2(n+3)=71

divide both sides by 2

n+3=35.5

minus 3 both sides

n=32.5

the number is 32.5

Answer 2

This problem can be interpreted different ways.

Here's how I interpret it:

Eight more than twice a number, increased by 3, is equal to 79. Find the number

Let n = the number

"Eight more": + 8

"Eight more than twice a number": 2n + 8

"Eight more than twice a number increased by 3": 2n + 8 + 3

"Eight more than twice a number increased by 3 is equal to 79.":

2n + 8 + 3 = 79

Now we solve the equation for n.

2n + 8 + 3 = 79

2n + 11 = 79

2n = 68

n = 34

The number is 34.