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3 years ago

Factor −3y−18 and choose the correct option.

Mathematics

1 answer:

balu736 [363]3 years ago

5 0

Answer:

-21

Step-by-step explanation:

because theres two negitives so it makes it a positive

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$3,254,107 what digit is in the hundred thousands place

Sergio [31]

The digit 2 would be in the hundred thousands place because if you say it out loud its "three million, two hundred fifty four thousand, one hundred and seven"

5 0

3 years ago

Read 2 more answers

sam said the absoulute value of 14 is -14. Kai said the absolute value of 14 is 14. Who is correct. Explain

Hoochie [10]

Answer:

Kai is right.

Step-by-step explanation:

Absolute Value is always positive.

4 0

3 years ago

PLEASE HELP!! Solve the equation. Please show your math work step by step. 5x −14=−34

MrMuchimi

Hey

The Answer is -4x

Heres the Step by Step work

You add 14 to each side because it is negative, so

5x-14=-34

+14|+14

and you will end up with

5x=-20

Divide 5 on each side, so

5x=-20

/5x | /5x

-20 / 5x =

x=-4

-4x

mark branliest plz

8 0

3 years ago

Enter the equivalent distance in km in the box.

devlian [24]

100 cm = 1m

To find 60 000cm, multiply by 600 :
60 000 cm = 600m

To convert from m to km, divide by 1000 :
600m ÷ 1000 = 0.6km

3 0

3 years ago

Simplify the expression state any excluded values 2a^2-4a+2 --------------- 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago