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const2013 [10]
3 years ago
6

Is x^2+13x-4=0 a quatratic function? Why?

Mathematics
1 answer:
zysi [14]3 years ago
8 0
Yes it is a quadratic function. A quadratic function contains the term x^2 and x^2 has the highest exponent in the whole function of a quadratic function. What I mean by this is for example x^3 + x^2 + 2x + 3 is not a quadratic. It includes x^2 but x^3 has the largest exponent. That makes that equation a cubic. Just for more info the largest exponent is referred to as the degree of the function so the degree of a quadratic function is always 2. Hope this helps!
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100 POINTS!!! PLEASE SHOW YOUR WORK. I WANT TO UNDERSTAND IT
Paraphin [41]

Answer:

100 POINTS!!! PLEASE SHOW YOUR WORK. I WANT TO UNDERSTAND IT

5 QUESTIONS

1) Pedro wants to make a 35% sugar solution. He has 3 ounces of a 56% sugar. How many ounces of a 14% sugar solution must he add to this to create the desired mixture?

2) Xavier wants to make 10 gallons of a 42% saline solution by mixing together a 50% saline solution and a 10% saline solution. How much of each solution must he use?

3) A passenger on a plane made a trip to Portland and back/ The plane took the same route coming back. On the trip there it flew 210 kilometers per hour and on the return trip it went 280 kilometers per hour. If the total trip took 5 hours, how long did the trip take coming back?

4) Amanda and Alexis live 4 miles apart. They decide to start walking toward each other's houses at the same time. Amanda walks at a rate of 3.5 miles per hour and Alexis walks at a rate of 4 miles per hour. How long will it take for them to meet?

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8 0
3 years ago
Find the measure of the indicated angle to the nearest degree
netineya [11]
The correct answer is 24
8 0
3 years ago
Read 2 more answers
Solve the inequality. Write the solution in set-builder notation.
Salsk061 [2.6K]
-4x - 17 ≥ -41
<u>       +17   +17</u>
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8 0
3 years ago
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
Read 2 more answers
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