Answer:
Two answers:
22 ≥ v
OR
v ≤ 22
Step-by-step explanation:
It's the same as solving for a variable in an equality. Imagine it as 17 = v - 5 for a moment. Simplify by subtracting 5 from both sides and re-add the inequality sign. This can be easily done since we are not multiplying or dividing, just adding and subtracting.
Z = (X-Mean)/SD
<span>z1 = (165 - 150)/15 = +1 </span>
<span>z2 = (135 - 150)/15 = - 1 </span>
<span>According to the Empirical Rule 68-95-99.7 </span>
<span>Mean +/- 1SD covers 68% of the values </span>
<span>100% - 68% = 32% </span>
<span>The remaining 32% is equally distributed below z = - 1 and z = +1 </span>
<span>32%/2 = 16%
</span>
<span>Therefore,
</span>
<span>a) Number of men weighing more than 165 pounds = 16% of 1000 = 160 </span>
<span>b) Number of men weighing less than 135 pounds = 16% of 1000 = 160</span>
3x+1/10=x-1/7
subtract 1/10 from both sides
3x=-1/7-1/10+x
subtract x from both sides
2x=-1/7-1/10
add -1/7 and -1/0
1/7=10/70
1/10=7/70
-10/70-7/70=-17/70
2x=-17/70
divide by 2 ro multiply by 1/2
x=-17/140
Answer:
20times
Step-by-step explanation:
A fair of die has 6sides.
If 4 appears 'once' out of a 6.
Then, 4 will appear 2times out of 12 i.e
6faces = 1time
12faces = 2times.
But remember that we want to know how many times 4 will appear out of a 120
120faces = x times
Since 6faces = 1time (i.e 4 occur one time in six faces)
cross multiplying:
6 × x = 120
x = 120/6
x = 20times
This means 4 will appear 20times out of a 120
