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Nikitich [7]
3 years ago
13

Write the expression in complete factored form 3c(c+3)-4(c+3)

Mathematics
2 answers:
zlopas [31]3 years ago
7 0

3c(c+3)-4(c+3)=3c^2+9c-4c-12=3c^2+5c-12


Andreyy893 years ago
6 0

Answer:

c+3 i think is correct

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Y is directly proportional to x when x=540 y=10 calculate the value of y when x=540.
zhuklara [117]

Answer:

Step-by-step explanation:

Y should still be 10 since x is 540

3 0
3 years ago
A bridge club had 22 members with a mean age of 68. Then two new members joined. One was 62 years old, and the other was 80 year
Allisa [31]
The mean went up 2 years
6 0
4 years ago
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One Positive number is five times another number the difference between the two numbers is 172 to find the numbers
Yakvenalex [24]

Answer:

x= 43, y=215

Step-by-step explanation:

Let one number be x,

Let the other number be y.

x= 5y

x - y= 172

Putting value of x in equation 2.

5y - y = 172

4y = 172

y= 172/4

y= 43

Putting value of y in eq. 1

x= 5(43)

x=215.

6 0
3 years ago
∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 1
Pavlova-9 [17]
We need to calculate major arc AE
arc AE + AB + BD + DE = 360°
arc AE + 112 + 28 + 112 = 360°
arc AE = 108°

From the attachment we can see Angle ACE = .5 * (AE -BD)
Angle ACE = .5 * (108 -28)
Angle ACE = .5 * (80)
Angle ACE = 40°

answer is C


8 0
4 years ago
a system of linear equations is given by the tables. one of the tables is represented by the equation y=-1/3x+7. The equation th
Jet001 [13]

Answer:

1). Other line is, y = \frac{1}{3}x+5

2). Solution of the system is (3, 6)

Step-by-step explanation:

From the table (1),

Let the equation of the line from the given table is,

y - y' = m(x - x')

Where m = slope of the line

(x', y') is a point lying on the line.

Choose two points from the table which lie on the line.

Let the points are (0, 5) and (3, 6)

Slope = m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                 = \frac{5-6}{0-3}

                 = \frac{1}{3}

Therefore, equation of the will be,

y - 5 = \frac{1}{3}(x-0)

y = \frac{1}{3}x+5 -------(1)

Let the other line from the table (2) is,

y - y" = m'(x - x")

Two points taken from this table are (0, 7) and (3, 6)

m' = \frac{7-6}{0-3}

    = -\frac{1}{3}

Equation of the line will be,

y - 7 = -\frac{1}{3}(x-0)

y = -\frac{1}{3}x+7 -------(2)

Therefore, equation of the other line will be, y = \frac{1}{3}x+5

By adding equations (1) and (2),

y + y = -\frac{1}{3}x+\frac{1}{3}x+5+7

2y = 12

y = 6

From equation (1),

6 = \frac{1}{3}x+5

\frac{1}{3}x=7-6

x = 3

Therefore, solution of the system is (3, 6).

6 0
4 years ago
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