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olchik [2.2K]
3 years ago
9

A dam generating electricity from water flowing downhill is an example of how systems

Physics
2 answers:
Snowcat [4.5K]3 years ago
6 0
<span>The generation of electricity is done through the concert of energy conversion. A dam generating electricity from water flowing downhill is an example of how systems take advantage of energy flowing from high to low. Turbines play a huge part in generating electric power after the water passes through the spinning turbines and this water is left back to the river.</span>
Jlenok [28]3 years ago
5 0

Answer:

The answer is the dam generates electricity taking advantage of energy flowing from high to low.

Explanation:

Basically, what the dam does is to store gravitational potential energy and converts it to kinetic energy. This conversion can be made since the water at one side is higher that the other side of the dam, therefore the higher side stores the potential energy and when it goes to the other side, the energy stored is converted to kinetic energy, which turn turbines generating electricity.

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An alternator consists of a coil of area A with N turns that rotates in a uniform field B around a diameter perpendicular to the
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Answer:

(a): \rm 2\pi f\ NBA\ \sin(2\pi ft)..

(b): 20.94 Volts.

Explanation:

<u>Given:</u>

  • Area of the coil = A.
  • Number of turns of the coil = N.
  • Magnetic field in which the coil is placed = B.
  • The frequency with which the coil is rotating = f.

<h2>(a):</h2>

The magnetic flux linked with a coil is defined as

\phi = N\vec B \cdot \vec A=\rm NBA\cos\theta

where,

  • \vec A is the area vector of the coil, directed along the normal to the plane of the coil.
  • \theta = angle between the magnetic field and the area vector of the coil.

Assuming that the magnetic field is along the normal to the plane of the coil, initially.

Therefore, at any later time t, the angle which the magnetic field makes with the normal to the plane of the coil is is given by

\rm \theta = 2\pi ft.

Therefore, the magnetic flux linked with the coil at any time t is given by

\rm \phi = NBA\cos(2\pi ft).

According to the Faraday's law of electromagnetic induction, the emf induced in the coil is given by

\rm e=-\dfrac{d\phi}{dt}\\=-\dfrac{d(NBA\cos(2\pi ft))}{dt}\\=-NBA\dfrac{d(\cos(2\pi ft))}{dt}\\=-NBA(-2\pi f\sin(2\pi ft))\\=2\pi f\ NBA\ \sin(2\pi ft).

<h2>(b):</h2>

The amplitude of the alternating voltage is the maximum value of the induced emf in the coil, the induced emf in the coil is maximum when \rm \sin(2\pi ft)=1.

Therefore, the amplitude of the alternating voltage is given by

\rm e_o=(2\pi f)NBA\ 1\\=2\pi ft \ NBA.

Given values are:

  • N = 100 turns.
  • A = \rm 10^{-2}\ m^2.
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  • f = 2000 rev/min = \rm 2000\times \dfrac1{60}\ rev/s = 33.33\ rev/s.

Putting all these values,

\rm e_o=2\pi \times 33.33\times (100)\times (0.1)\times (10^{-2})=20.94\ Volts.

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