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3 years ago

What are the elements of NaCl

Physics

1 answer:

Lana71 [14]3 years ago

4 0

The elements in NaCl are Na -sodium and Cl - chlorine

<u>Explanation:</u>

sodium chloride (NaCl) is also known as common salt. The molar ratio of NaCl is 1:1 and has the molar mass of 22.99 and 35.45 respectively. The molar mass of NaCl is 58.443 g/mol. It is a odorless and colourless cubic crystal.

It has the melting point of 800.7°C and has the boiling point of 1465°C. It has a face centered cubic crystal structure.The elements in NaCl are Na -sodium and Cl - chlorine

$2Na+Cl_{2}$ → $2NaCl$

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B) A non-inductive load takes a current of 15 A at 125 V. An inductor is then connected

levacccp [35]

Answer:

i. 43.5 mH ii. 16 Ω. In phasor form Z = (8.33 + j13.66) Ω iii 58.64°

Explanation:

i. The resistance , R of the non-inductive load R = 125 V/15 A = 8.33 Ω

The reactance X of the inductor is X = 2πfL where f = frequency = 50 Hz.

So, x = 2π(50)L = 100πL Ω = 314.16L Ω

Since the current is the same when the 240 V supply is applied, then

the impedance Z = √(R² + X²) = 240 V/15 A

√(R² + X²) = 16 Ω

8.33² + X² = 16²

69.3889 + X² = 256

X² = 256 - 69.3889

X² = 186.6111

X = √186.6111

X = 13.66 Ω

Since X = 314.16L = 13.66 Ω

L = 13.66/314.16

= 0.0435 H

= 43.5 mH

ii. Since the same current is supplied in both circuits, the impedance Z of the circuit is Z = 240 V/15 A = 16 Ω.

So in phasor form Z = (8.33 + j13.66) Ω

iii. The phase difference θ between the current and voltage is

θ = tan⁻¹X/R

= tan⁻¹(314.16L/R)

= tan⁻¹(314.16 × 0.0435 H/8.33 Ω)

= tan⁻¹(13.66/8.33)

= tan⁻¹(1.6406)

= 58.64°

3 0

3 years ago

Which of these diagrams most accurately illustrates what happens when a ray of light from underwater strikes the smooth surface

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3 years ago

Read 2 more answers

A 2.0-kg mass is oscillating about the origin at 24 rad/s. The amplitude of the oscillations is 0.040 m. At what position is the

Darya [45]

Answer:

0.0327 m

Explanation:

m = 2 kg

ω = 24 rad/s

A = 0.040 m

Let at position y, the potential energy is twice the kinetic energy.

The potential energy is given by

U = 1/2 m x ω² x y²

The kinetic energy is given by

K = 1/2 m x ω² x (A² - y²)

Equate both the energies as according to the question

1/2 m x ω² x y² = 2 x 1/2 m x ω² x (A² - y²)

y² = 2 A² - 2 y²

3y² = 2A²

y² = 2/3 A²

y = 0.82 A = 0.82 x 0.040 = 0.0327 m

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3 years ago

What does it mean for their to be a net force on an object vs no net force? Which one is described as balanced forces and which

STatiana [176]

It’s like the force put against something or someone✨

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2 years ago

A 10- kilogram block is pushed across a horizontal surface with a horizontal force of 20 N against a friction force of 10 N. The

Temka [501]

Answer:

$1m/s^2$

Explanation:

Mass of block=10 kg

Applied horizontal force =F=20 N

Friction force=f=10 N

We have to find the acceleration of block.

Net force=Applied horizontal force-friction force

$ma=F-f$

Where F= Horizontal force

f=Friction force

m=Mass of object

a=Acceleration of object

$10a=20-10=10$

$a=\frac{10}{10}=1 m/s^2$

Hence, the acceleration of the block= $1m/s^2$

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3 years ago