Question

If g(x)= x+1/x-2 and h(x) = 4-x, whAt is the value of (g•h)(-3)

Answer 1

( * means multiply) if you mean " / "as devided. Then:

[Simplify]1.

( x + 1/x - 8 - x -3 )

[Collect like terms]2.

(( x - x ) + 1/x - 8 ) * -3

[Simplify]3.

( 1/x - 8 ) x -3

[Answer]4.

-3( 1/x - 8)

Answer 2

Answer:  The required value of the given expression is 1.6.

Step-by-step explanation:  We are given the following two functions :

$g(x)=\dfrac{x+1}{x-2},~~~~~h(x)=4-x.$

We are to find the value of (g ° h)(-3).

We know that

for any two functions p(x) and q(x), the compositions of functions is defined as

$(p\circ q)(x)=p(q(x)).$

So, for the given functions, we have

$(g\circ h)(x)=g(h(x))=g(4-x)=\dfrac{4-x+1}{4-x-2}=\dfrac{5-x}{2-x}.$

Therefore, we get

$(g\circ h)(-3)=\dfrac{5-(-3)}{2-(-3)}=\dfrac{5+3}{2+3}=\dfrac{8}{5}=1.6.$

Thus, the required value of the given expression is 1.6.