A. <span>0.16 + 0.193 + 0.222 + 0.233 + 0.067 + 0.125 = 84
</span>probabilities are all between 0 and 1 but does not add to 1.
<span>B. 0.35+0.18+ 0.21+ 0.06+ 0.17+ 0.03 = 1
</span>probabilities are all between 0 and 1 and also <span>add to 1.
</span><span>C. (0.01) 11+ (0.01) 12+ (0.01) 13 = 0.11+0.12+0.13 =0.36
</span>probabilities are all between 0 and 1 but does not add to 1.
D. 0.16+0.12+ 0.02+ 0.08+ 0.22+ 0.05+ 0.15+ 0.02+ 0.18 = 1
probabilities are all between 0 and 1 and also add to 1.
E. 0.12-0.02+0.18+0.08+0.15+0.05+0.16+0.27+0.02+ 0.36 -0.15 -0.22 =1
probabilities are all between 0 and 1 and also <span>add to 1.</span>
Answer:
I believe the answer is D. Number line from 0 to 4 is divided into 20 equal parts. Number line is grouped into 10 equal parts.
Step-by-step explanation:
She can make 10 dresses if you split the number line into 20 parts and find 2/5. Therefore, it would then be grouped into 10 parts, each part 2/5ths of a yard.
Answer: a = 3∛2
<u>Step-by-step explanation:</u>
ab⁴ = 384 --> a = 384/b⁴
Substitute a = 384/b⁴ into the second equation to solve for "b".
a²b⁵ = 4608
![\bigg(\dfrac{384}{b^4}\bigg)^2\cdot b^5=4608\\\\\\\dfrac{147,456b^5}{b^8}=4608\\\\\\\dfrac{147,456}{b^3}=4608\\\\\\\dfrac{147,456}{4608}=b^3\\\\\\32=b^3\\\\\\\sqrt[3]{32} =b\\\\\\2\sqrt[3]{4} =b](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B384%7D%7Bb%5E4%7D%5Cbigg%29%5E2%5Ccdot%20b%5E5%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456b%5E5%7D%7Bb%5E8%7D%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456%7D%7Bb%5E3%7D%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456%7D%7B4608%7D%3Db%5E3%5C%5C%5C%5C%5C%5C32%3Db%5E3%5C%5C%5C%5C%5C%5C%5Csqrt%5B3%5D%7B32%7D%20%3Db%5C%5C%5C%5C%5C%5C2%5Csqrt%5B3%5D%7B4%7D%20%3Db)
Substitute b = 2∛4 into the first equation to solve for "a".
ab⁴ = 384
a(2∛4)⁴ = 384
a = 384/(2∛4)⁴
a = 24/4∛4
= 6/∛4
= 6(∛2)/2
= 3∛2
There are seven females and nineteen males in the spanish class.
Answer:
the answer is D
Step-by-step explanation: