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malfutka [58]
3 years ago
6

Melissa wrote this expression to describe the number of pencils she used during the school year. 

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0
The answer would be c
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Find two fractions equivalent to each fraction.<br><br> 3 over 9<br><br> 20 over 22
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Read 2 more answers
(t-distribution) A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. To m
statuscvo [17]

Answer:

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A manufacturing firm claims that the batteries used in laptop computers will last an average of 50 months. This means that \mu = 50.

We found that the sample had a average lifespan of 47.3 months, and a standard deviation of s = 9 months. What is the probability that we find this lifespan for our sample average, or something even shorter?

We have to find the pvalue of Z when X = 47.3.

We are working with a sample mean, so we use the standard deviation of the sample in the place of \sigma. That is s = 9

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{47.3-50}{9}

Z = -0.3

Z = -0.3 has a pvalue of 0.3821.

There is an 38.21% probability that we find this lifespan for our sample average, or something even shorter.

7 0
3 years ago
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