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3 years ago

14

A parabola has a vertex at (-6, 2) and opens down. Which of the following represents the

1 answer:

Setler [38]3 years ago

4 0

Answer:

I don't see any choices but I think the axis of symmetry is x=-6.

Step-by-step explanation:

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>…_~§-+*First Answer Gets Brainliest*+-§~_…<<br> Questions In the picture!

zysi [14]

Answer:

1. If x=5, 3*5=15, 15*15=225 + y (3) = 228.

2. If y=4, then 10*4 = 40, 4^2 is 16, so 40 + 16 is 56.

I might be wrong, but the first one you answered, x^2, x= 1/2, I think that is wrong. when something is squared, you don't go, "Oh, well since 1/2 equals 1, that's the answer." The way to figure out something like this is... 1/2 times 1/2, which is .25, or 1/4. Another example: 3^5 . The way to find this out is 3*3*3*3*3 = 243. But you don't go 3*5, because that answer would be 15, which is not correct.

7 0

3 years ago

7. The area of a square piece of cardboard is 70 cm2. What is the

astra-53 [7]

Answer:

8.3 cm

Step-by-step explanation:

<h2>so area of a square= side×side</h2><h2>since all sides are equal in a square</h2><h2>so= s×s=70cm²</h2><h2>√s²=√70</h2><h2>s=8.3 cm</h2>

7 0

4 years ago

Read 2 more answers

I need some help plz

aksik [14]

Answer:

B

Step-by-step explanation:

The most reasonable one is B because its 7 for side B and the rest for B are either bigger or equal to the given number

3 0

3 years ago

Read 2 more answers

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

3 years ago

Amy is analyzing a job offer.

Sunny_sXe [5.5K]

The answer is 43,500

8 0

3 years ago

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