A flagpole is supported by a wire fastened 60 feet from its base. The wire is longer than the height it reaches on the flagpole.
Find the length of the wire.
1 answer:
Answer:
135.5ft
Step-by-step explanation:
THIS COMPLETE THE QUESTION
flagpole is supported by a wire fastened 60 feet from its base. The wire is 14 feet longer than the height it reaches on the flagpole. Find the length of the wire.
Let X be the length of the wire
Let y be the height of the pole
X= Y + 14
Y= X -14
We can form a right angle triangle form this, where X denote the Hypotenose, Y is the Opposite, and 60feet is the Adjacent.(CHECK THE ATTACHMENT FOR THE TRIANGLE)
Using Pythagoras theorem
X²= 60² + Y²
X² = 3600 + Y²
if we subsitute for Y we have
X² = 3600 + (X -14)²
X² = 3600 +X² -14X-14X+196
X²-X²+ 28X= 3600+196
28X= 3796
X= 3796/28
=135.5ft
hence length of the wire is 135.5ft
You might be interested in
Answer:
24 feet
Step-by-step explanation:
Given that:
The length of the rectangle is 6 times the side of a cement square.
Now, this rectangle is formed from 6 squares;
The total area of the path of this square = 96 square feet;
The area of each square now = 96/6 = 16 square feet
Recall that:
Area of a square = S²
where S is the side length
16 = S²
S =
S = 4 ft
The length of the path in feet now is: L × w
= 6 × 4
= 24 feet.