Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
So first you would evaluate the power making the 4^3=64 then keep the rest of the problem the same.... then add the numbers 64+8 since their the whole numbers and that would equal 72 so now the problem should be 72-9/y. After that you write all the numerators above the common denominator making the final answer to be 72y-9/y
Step-by-step explanation:
circumference of a circle
2×pi×r
area of a circle
pi×r²
r (radius) = diameter/2 = 1.5ft
we shall assume pi to be 3.14
circumference is
2×3.14×1.5 = 3.14×3 = 9.42 ft
area is
3.14 × 1.5² = 3.14×2.25 = 7.065 ft²
The answer is 18. Just take the number that comes later and simply subtract from the original number. EXAMPLE- 138-120=18. Hope this helps.
