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hram777 [196]
3 years ago
7

Can someone help me with this

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

19 m

Step-by-step explanation:

This is Geometric progression with

\left \{ {{u_1=1,\: u_2 =2} \atop {u_n=2^{n-1}u_1} \right.

Then the fomular of sum is

S=u_1\frac{2^n-1}{2-1} =1\times(2^n-1)=2^n-1\\To\: save\: 1 \:million\: then \; our \:sum \: will \: be\: 1000000\\Hence,\\2^n-1=1000000\\2^n=1000001\\n=log_{2}{1000001}\approx19,9\\Thus, it\:would \;be \:19 \:months \:before\: we\: saved \:1000000 \:pounds

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Find the equation,in standard form, of the line passing through the point (2,-3) and (4,2)
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The standard form:

Ax+By=C

The point-slope form:

y-y_1=m(x-x_1)

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(x₁, y₁) - point

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, -3) and (4, 2). Substitute:

m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}

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2y=5x-16         <em>subtract 5x from both sides</em>

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\boxed{5x-2y=16}

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Answer:

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Step-by-step explanation:

The given parameters are;

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The expected value is given as follows

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No claim                        0.9                 $1,400                                       $1260

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