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Kryger [21]
3 years ago
10

Help, don’t understand this problem.

Mathematics
2 answers:
Mila [183]3 years ago
8 0

Answer:

(2, 3 )

Step-by-step explanation:

Given the 2 equations

3x - 5y = - 9 → (1)

x + 2y = 8 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate the x- term, that is

- 3x - 6y = - 24 → (3)

Add (1) and (3) term by term to eliminate x

(3x - 3x) + (- 5y - 6y) = (- 9 - 24), that is

- 11y = - 33 ( divide both sides by - 11 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for x

Substituting in (2)

x + 2(3) = 8

x + 6 = 8 ( subtract 6 from both sides )

x = 2

Solution is (2, 3 )

GuDViN [60]3 years ago
8 0

Answer:

Step-by-step explanation:

hello :

here is an solution :

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A^2 - b^2 = (a - b)( a +b);
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What is the median of 36 45 29 39 51 49
Murrr4er [49]
 29 36 39 45 49 51

39 + 45 = 84

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The difference between a number and 8 is 11
quester [9]

Answer:

The difference between 19 and 8 is 11.

Step-by-step explanation:

Given:

The difference between a number and 8 is 11

Find the number.

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Let the unknown number be =x

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x-8

We are given that the difference =11

So we can write the equation to find x as :

x-8=11

Using additive property to solve for x

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Write the ratio as a fraction in simplest form. 32:42
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Records indicate that for parts coming out a hydraulic repair shop at an airplane rework facility, 30\% will have a shaft defect
mrs_skeptik [129]

Answer:

P(A|B) = P(A∩B)/P(B) = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

Step-by-step explanation:

Conditional probability P(A|B) can be expressed as;

P(A|B) = P(A∩B)/P(B) .....1

Given;

30% will have a shaft defect,

15% will have a bushing defect,

and 65% will be defect-free

Total probability = 100% = P(shaft or/and bushing defect) + P(defect free)

P(shaft or/and bushing defect) = 100% - P(defect free)

= 100% - 65% = 35%

And

P(shaft or/and bushing defect) = P(shaft def only) + P(bushing def only) + P(shaft and bushing defect)

P(shaft or/and bushing defect) = P(shaft defect) + P(bushing defect) - P(shaft and bushing defect)

Substituting the values we have;

35% = 30% + 15% - P(shaft and bushing defect)

P(shaft and bushing defect) = 45% - 35% = 10%

Let A="The item has at least one type of defect"; and B="The item has only a shaft defect".

P(A) = P(shaft or/and bushing defect) = 35%

P(B) = P(shaft only defect) = 30% - 10% = 20%

P(A∩B) = 20%

Substituting into equation 1

P(A|B) = P(A∩B)/P(B) = 20%/20%

P(A|B) = 1/1 = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

5 0
3 years ago
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