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algol13
3 years ago
7

I don’t know how many times i’ve been going through this question but i need some serious help

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0
\cfrac{x^2-81}{x^2\underline{-6x}-27} \cdot \cfrac{x+3}{x}= \cfrac{(x-9)(x+9)}{x^2\underline{+3x-9x}-27} \cdot \cfrac{x+3}{x}= \\ \\ \\ \\=\cfrac{(x-9)(x+9)}{x(x+3)-9(x+3)} \cdot \cfrac{x+3}{x}=\cfrac{(x-9)(x+9)}{(x+3)(x-9)} \cdot \cfrac{x+3}{x}= \boxed{\frac{x+9}{x} }
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Suppose you accumulated $500,000, perhaps from many years of saving. You put the money in a savings plan earning 6% compounded m
Brut [27]
The amortization formua I'm familiar with assumes payments are made at the end of the period, so we'll use it for the part after the first payment has already been made.
.. A = 4,000
.. P = 500,000 -4000 = 496,000
.. i = 0.06
.. n = 12
.. t = to be determined
And the formula is
.. A = Pi/(n(1 -(1 +i/n)^(-nt))) . . . . . amortization formula with payments at the end of the period
.. 1 -(1 +i/n)^(-nt) = Pi/(An) . . . . . . rearrange to get "t" factor in numerator
.. 1 -Pi/(An) = (1 +i/n)^(-nt) . . . . . . get "t" factor by itself
.. log(1 -Pi/(An)) = -nt*log(1 +i/n) . . . . use logarithms to make the exponential equation into a linear equation
.. log(1 -Pi/(An))/(-n*log(1 +i/n)) = t . . . . divide by the coefficient of t
.. t = 16.1667 . . . . . years (after the first monthly withdrawal)

The plan will support withdrawals for 16 years and 3 months (195 payments).
4 0
3 years ago
A=. B= 2.6 c=6.2 using Pythagorean Theron what is a?
Kryger [21]
Hello!
So you will use the Pythagorean Theron equation which is Asquare + bsquare=C square
Plug in what you are given to find the missing piece

A square+ (2.6)square= (6.2) square
Asquare+ 6.76= 38.44
(Subtract 6.76to both sides to isolate A)
Asquare= 31.68
(Take the square root of both sides to find out what A is)
A=5.628

6 0
4 years ago
Read 2 more answers
Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had 3 times as many d
nadya68 [22]
Oyebolatoba Beginner
Let d = # digital cameras
Let m = # manual cameras

d + m = 240 equation 1

(d-82) = 3(m-26) equation 2
d - 82 = 3m - 78
d - 3m = 82 - 78
d - 3m = 16 equation 2 simplified

We have two equations with 2 unknowns:

d + m = 240
d - 3m = 16 subtract equation 1 from equation 2
---------------
-4m = -224
m = -224/-4
m = 56

d + m = 240
d = 240-m
d = 240-56
d = 184

He started with 184 digital cameras and 56 manual cameras

5 0
3 years ago
Which inequalities are true and false
Nutka1998 [239]
  • 5×1 < 3 __ false
  • 5×3 < 3 ___false
  • 5×-2 <3 ___true

7 0
3 years ago
Why is mental addition and subtraction important when you learn more difficult concept
Alex Ar [27]
It is important so you can be more fluent or faster in knowing bigger problems
7 0
4 years ago
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