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3 years ago

12

I WILL GIVE BRAINLIEST! Which table of values corresponds to the graph below?

2 answers:

Goshia [24]3 years ago

6 0

Answer:

the very bottom graph

Step-by-step explanation:

all of the points listed on the table match the graph

x values is found on the x axis (left to right)

y values are found on the y axis (up and down)

KonstantinChe [14]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

From graph, points (2, 0) and (0, -2).

slope m = (y₂ - y₁) / (x₂ - x₁)

= (-2 - 0) / (0 - 2)

= -2 / -2

= 1

y-intercept using anyone of the above points and m:

y = mx + b

0 = 1(2) + b

0 = 2 + b

b = -2

Equation of line using m and b:

y = 1x - 2

Use y = 1x - 2 to check the points given in tables:

All points in below table seems to work.

(0, -2)

-2 = 0 - 2

-2 = -2

(1, -1)

-1 = 1 - 2

-1 = -1

(2, 0)

0 = 2 - 2

0 = 0

(4,2)

2 = 4 - 2

2 = 2

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Nina [5.8K]

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2 years ago

Read 2 more answers

10. The perimeter of a regular nonagon is 162 inches. The apothem is 97.8 inches. Find the area.

Katen [24]

Answer:

The area of the regular nonagon is 7921.8 square inches.

Step-by-step explanation:

Geometrically speaking, the area of a regular polygon is determined by following area formula:

$A = \frac{p\cdot a}{2}$ (1)

Where:

$A$ - Area of the regular polygon, in square inches.

$p$ - Perimeter, in inches.

$a$ - Apothem, in inches.

If we know that $p = 162\,in$ and $a = 97.8\,in$ , then the area of the regular nonagon is:

$A = 7921.8\,in^{2}$

The area of the regular nonagon is 7921.8 square inches.

8 0

3 years ago

RS=2x-8, ST = 11, RT = x+10

ziro4ka [17]

Answer:

$Equation~=~\Large\boxed{2x+3=x+10}$

$x~=~\Large\boxed{7}$

$RS~=~\Large\boxed{6}$

$RT~=~\Large\boxed{17}$

Step-by-step explanation:

<u>Given information</u>

$RS=2x-8$

$ST=11$

$RT=x+10$

<u>Derived expression from the given information</u>

<em>Presumably, I think this is a combination of segments</em>

$RS+ST=RT$

<u>Substitute values into the given expression</u>

$(2x-8)+(11)=(x+10)$

<u>Combine like terms</u>

<em>The following is the expression</em>

$\Large\boxed{2x+3=x+10}$

<u>Subtract 3 on both sides</u>

$2x+3-3=x+10-3$

$2x=x+7$

<u>Subtract x on both sides</u>

$2x-x=x+7-x$

$\Large\boxed{x=7}$

<u>Substitute the x value into corresponding expressions to determine the final value</u>

$RS=2x-8=2(7)-8=14-8=\Large\boxed{6}$

$RT=x+10=(7)+10=\Large\boxed{17}$

Hope this helps!! :)

Please let me know if you have any questions

3 0

1 year ago

28÷x=168<br>What is the value of "x"

coldgirl [10]

It is 1/6 or .16 I used Photomath

7 0

3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago