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Irina18 [472]
3 years ago
5

180% of what number is 27

Mathematics
2 answers:
Vika [28.1K]3 years ago
6 0

Answer:

15.

Step-by-step explanation:

180% is equivalent to 1,8 so

1.8 x = 27    where x is the required number.

x = 27/1.8

= 15.

ser-zykov [4K]3 years ago
5 0

Answer:

15

Step-by-step explanation:

To figure this out you have to use the equation is over of equals percent over 100.

In this problem you are given the percent, 180, and the is, 27.

So you are trying to find the of so in the equation you will replace of with x.

27/x = 180/100

Now you have to do Cross Product Property

So 27*100 = 2700

180*x = 180x

180x = 2700

Now divide 180 by itself and 2700

180/180 = 1

2700/180 = 15

x = 15

So 180% of 15 is 27

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Answer:

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Step-by-step explanation:

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3 years ago
Among all monthly bills from a certain credit card company, the mean amount billed was $465 and the standard deviation was $300.
Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10.

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when X = 500. So

Z = \frac{X - \mu}{s}

Z = \frac{500 - 465}{10}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

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