Let time be x distance be y
Put value in eq(2)
Put it in eq(1)
I mean I think so I’m not completely sure it’s a really hard question
Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
Read more about measures of center
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Answer:
7.50 cheaper than buying individually
Step-by-step explanation:
13.50/6=2.25
3.50*6=21.00
21.00-13.50= 7.50
6/8 , just add both fractions together for the total, as they already have common denominators.
