False
-3 is not greater than positive 3
This revolves around exact trig values - no easy way to say this, you just need to memorise them. They are there for sin cos and tan, but I will give you the main tan ones below - note this is RADIANS (always work in them when you can, everything is better):
tan0: 0
tanpi/6: 1/sqrt(3)
tanpi/4: 1
tanpi/3: sqrt(3)
tanpi/2: undefined
Now we just need to equate -2pi/3 to something we understand. 2pi/3 is 1/3 of the way round a circle, so -2pi/3 is 1/3 of the way round the circle going backwards (anticlockwise), so on a diagram we already know it's in the third quadrant of the circle (somewhere between pi and 3pi/2 rads).
We also know it is pi/3 away from pi, so we are looking at sqrt(3) or -sqrt(3) because of those exact values.
Now we just need to work out if it's positive or negative. You can look up a graph of tan and it'll show that the graph intercepts y at (0,0) and has a period of pi rads. Therefore between pi and 3pi/2 rads, the values of tan are positive. Therefore, this gives us our answer of sqrt(3).
Answer:
73
Step-by-step explanation:
1. <span>4x – 20 = 5y
so 5y = </span><span>4x – 20
divide both sides by 5
y = (4/5)x - 4
2. x-intercept is at y=0
so (4/5)x - 4 = 0
x = 5
so it is (5,0)
3. y-intercept is at x=0, y = 0 - 4 = -4
so it is (0,-4)
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Answer:
a. 13.7084 oz.
Step-by-step explanation:
Formula for Lower Control Limit =
(LCL = x-bar - A²R-bar)
x - bar = 14 oz
A2 = 0.729
R - bar = 0.4 oz
= 14 - 0.729 × 0.4
= 14 - 0.2916
= 13.7084oz
