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3 years ago

How to find the roots of a graph?

1 answer:

8 0

Find the roots of a graph by looking at where the parabola hits the x-axis on both sides. In the calculator you work put 2nd+trace+2 and go below the point, press enter and above the point and press enter 2 times for your answer.

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What is the value of x in the inequality 7x-26>=3(3x-2)

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Answer:

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3 years ago

Which expressions can you use to find 70% of 58

Ahat [919]

Answer:

C and E

Step-by-step explanation:

70% of 58

70/100 × 58

0.70 × 58

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3 years ago

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In a class of 25 students , 12 have taken in mathematics , 8 have taken mathematics but not biology . Find

lina2011 [118]

Answer:

I.4

ii.13

Step-by-step explanation:

....ur welcome........

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3 years ago

Read 2 more answers

20 POINTS!!!!!!!!

lorasvet [3.4K]

You are asked to find the missing value in

... 40 + ? = 70

given that it is also the solution to

... ? + 5 = 35

Either way, you subtract the constant that is on the same side of the equation as the unknown.

... 40 + ? - 40 = 70 - 40

... ? = 30 . . . . the missing value

_____

You can check to see if this also satisfies the equation

... 30 + 5 = 35 . . . . . . . true

7 0

3 years ago

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

7 0

3 years ago