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2 years ago

How to find the roots of a graph?

1 answer:

8 0

Find the roots of a graph by looking at where the parabola hits the x-axis on both sides. In the calculator you work put 2nd+trace+2 and go below the point, press enter and above the point and press enter 2 times for your answer.

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2. Write the expressions using an exponent. Then solve.

Maurinko [17]

B. Five cubed because there at 5 2s there and 2*2*2*2*2 would be the same thing as saying 5^2

7 0

2 years ago

Read 2 more answers

Given the following system of equations, what is the value of the y-coordinate of the solution?

Alina [70]

9/4 is the answer if you have any questions please let me know

4 0

2 years ago

A company is creating a box without a top from a piece of cardboard, but cutting out square corners with side length x.

Volgvan

Answer: Choice B) The expression (10-2x)(30-2x)x represents the volume of the box

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The original width is 10 inches. The width reduces to 10-2x inches after we cut off the top two corners of the rectangle. We can think of it as taking 10 and subtracting off two copies of x like so: 10-x-x = 10-2x

Similarly, the length goes from 30 inches to 30-2x inches. This time we're taking off the top and bottom corners (focus on either side it doesn't matter).

The height of the box is x inches due to this portion being folded up.

Volume of box = (width)*(length)*(height)
Volume of box = (10-2x)(30-2x)x

Note: the units for the answer are in cubic inches which can be written as "in^3" (inches cubed).

6 0

2 years ago

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the graph F(x) shown below resembles the graph of g(x) = |x| but it has been flipped over the x axis which of the following is t

Radda [10]

Answer:

f(x)=-|x|

Step-by-step explanation:

We have been given a graph of f(x) which resembles with the graph of function g(x) where g(x)=|x|.

It says that graph is flipped over the x-axis.

Now we have to find about which of the following choice correctly describes the given graph.

We know that |x| means absolute value of x so that means g(x)=|x| is absolute function in shape of V.

We know that flipping over x-axis can be done by changing f(x) into -f(x).

<u>Hence correct answer is choice D) F(x)=-|x|</u>

6 0

2 years ago

Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.

Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

$\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]$

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

$\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]$

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

$\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]$

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0

2 years ago