1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artyom0805 [142]
3 years ago
13

What is the value of 4 in 2,483,175?

Mathematics
2 answers:
viktelen [127]3 years ago
5 0

Answer:

Im pretty sure it is 400,000 if this is place values, let me know if I'm wrong, I hope this helped you!

Step-by-step explanation:

UNO [17]3 years ago
3 0

Answer:

400,000

Step-by-step explanation:

You might be interested in
Write 5 pounds for $2.49 a unit rate round to the nearest hundredth
slava [35]

About $0.50 per pound.

3 0
3 years ago
The letters 's', 't', 'u', 'd', 'y', 'i', 's', 'l', 'a', 'n', 'd' are placed in a bag. one letter is randomly selected from the
Aleks [24]

Answer:

<em><u>7/11</u></em>

Step-by-step explanation:

There are 11 letters in 'S', 'T', 'U', 'D', 'Y', 'I', 'S', 'L', 'A', 'N', 'D', so there are 11 letters in the bag.

There are 7 consonants in the bag.

So, the probability of selecting a consonant is 7 out of 11, or 7/11

3 0
3 years ago
Integrate 1 - x / x(x2 + 1) d x by partial fractions.
solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

step 1:-   by using partial fractions

[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }......(1)

<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 }  d x -\int\limits \frac{1}{x^{2}+1 }  d x

by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

\int\limits tan^{-1}x  dx =\frac{1}{1+x^{2} } +C.....(c)

<u>step 4:-</u>

by using above integration formulas (a,b,and c)

we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

6 0
3 years ago
Can someone please help with this question
maksim [4K]

Answer:

X = 7.2

Step-by-step explanation:

Hello

For the triangle of right side, using Pytagoras:

(2.5)^2 + b^2 = 6^2

6.25 + b^2 = 36

b^2 = 36 - 6.25

b^2 = 29.75

b = 5.45

Now we can to find X using again Pytagoras:

3^2 + (5.45)^2 = x^2

9 + 29.75 = x^2

38.75 = x^2

X = 7.2

Best regards

5 0
3 years ago
If the gradient of a line, A, is 4, what is the gradient of a line which is perpendicular to A?
Ne4ueva [31]

Answer:

m = - 1/4

Step-by-step explanation:

When two line is perpendicular to each other the product of them is - 1

So let the other line be B

Gradient of B = t

Gradient of A = 4

t \times 4 =  - 1 \\  t =  - \frac{1}{4}

therefore m = - 1/4

8 0
2 years ago
Other questions:
  • Divide and answer in simplest form:
    7·2 answers
  • 3 mi = how many. Ft i need help had 2 weeks to do now its due tomorrow HELP PLZ
    9·1 answer
  • What are the non overlapping angles
    6·1 answer
  • Simplify 3/4(3x+6)-1/4(5x-24)
    15·1 answer
  • The temperature at sunrise is 36F. Each​ hour, the temperature rises 4F. Write an equation that models the temperature​ y, in de
    12·1 answer
  • Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T
    12·2 answers
  • "the distribution of means is the correct comparison distribution when"
    13·1 answer
  • Can someone please help me
    8·1 answer
  • 8 times the sum of 2 and 15
    15·2 answers
  • 64 for each cube there is a bigger cube that is 3/4feet on each side what is the volume in cubic feet in fraction form if necess
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!