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musickatia [10]
3 years ago
14

Angles 4, 5, and 6 are in the ratio 2:5:3. Find the measure of each angle

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

Answer:

The angles 4, 5 and 6 are 36, 90 and 54 respectively.

Step-by-step explanation:

First, let's find the total number of parts:

2 + 5 + 3 = 10

The amount of degrees per part is 180 / 10 = 18.

Now, we multiply that factor to the ratio:

2*18 : 5*18 : 3*18//36:90:54

Thus, the angles 4, 5 and 6 are 36, 90 and 54 respectively.

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3 years ago
A borrower had a loan of $ 60 comma 000.00 at 4 % compounded annually comma with 8 annual payments. Suppose the borrower paid of
quester [9]

Answer:

The amount needed to pay off the loan after 4 years is $70,192

Step-by-step explanation:

When interest is compounded annually, total amount A after t years is given by:

A = P(1 + r)^{t}

where P is the initial amount (principal), r is the rate and t is time in years.

From the question:

P = $60,000

r = 4% = 0.04

t = 4

A = 60000(1 + 0.04)^{4} \\A = 60000(1.04)^{4}\\A = 60000 * 1.16985856\\A = 70191.5136\\A = 70192

The amount needed to pay off the loan after 4 years is $70,192

If we divide the amount by four, we will get the amount that is paid yearly (70192/4 = 17548). $17,548 is paid yearly.

7 0
3 years ago
Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

It is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x .

Step-by-step explanation:

We already have the identity of x as \sin ^{2}x + \cos ^{2}x = 1 .......... (1)  .

So, from equation (1) we can write that

\cos ^{2} x = 1 - \sin ^{2} x

⇒ 6\cos ^{2} x = 6 - 6 \sin ^{2} x

⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
3 years ago
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