Answer:
ΔABC≅ΔDEC by AAS
Step-by-step explanation:
You can use the AAS method of congruency.
Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent
Hope this helped.
The first answer is B: 2 1/2
4 5/6 is put there twice except the last one is subtracting so you can put, 4 5/6 - 4 5/6 = 0 therefore the only number left is 2 1/2
the second one I really don't know sorry:(
The third answer is C because the cases come in 24. But they didn't tell you how many case she brought so the variable has to be by 24 and they took 43 which is the subtracting factor. So the answer is C.
And I also don't know the last one again sorry:(
Because when you subtract a negative number the signs cancel out and become and addition problems
63/8 is 7.875, or 7 remainder 7.
