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Evgen [1.6K]
4 years ago
6

Evaluate 3 over 2y-3 + 5 over 3z when y=6 and z=3.

Mathematics
1 answer:
anastassius [24]4 years ago
3 0

Answer:

\frac{8}{9}Step-by-step explanation:[tex]\frac{3}{2y-3}  + \frac{5}{3z}    y = 6, z = 3

Substitute values into the expression:

\frac{3}{2(6)-3}  + \frac{5}{3(3)}

Simplify both fractions:

\frac{3}{9}  + \frac{5}{9}

Add the fractions:

[tex]\frac{8}{9}

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hello :

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