Evaluate 3 over 2y-3 + 5 over 3z when y=6 and z=3.

Mathematics

1 answer:

anastassius [24]4 years ago

3 0

Answer:

$\frac{8}{9}Step-by-step explanation:[tex]\frac{3}{2y-3} + \frac{5}{3z}$ y = 6, z = 3

Substitute values into the expression:

$\frac{3}{2(6)-3} + \frac{5}{3(3)}$

Simplify both fractions:

$\frac{3}{9} + \frac{5}{9}$

Add the fractions:

[tex]\frac{8}{9}

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YA is the angle bisector of ZXYZ. If mZXYZ = 52°, what is mZZYA?

antoniya [11.8K]

Given:

$YA$ is the angle bisector of $\angle XYZ$ .

$m\angle XYZ=52^\circ$

To find:

The measure of $m\angle ZYA$ .

Solution:

It is given that $YA$ is the angle bisector of $\angle XYZ$ . It means

$m\angle XYA=m\angle ZYA$ ...(i)

Now,

$m\angle XYA+m\angle ZYA=m\angle XYZ$

$m\angle ZYA+m\angle ZYA=52^\circ$ [Using (i)]

$2m\angle ZYA=52^\circ$

Divide both sides by 2.

$m\angle ZYA=\dfrac{52^\circ}{2}$

$m\angle ZYA=26^\circ$

Therefore, the required value is $m\angle ZYA=26^\circ$ .

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a trapezoid has one base of 10 inches,an altitude of 6 inches and an area of 51 square inches, find the length of the other base

Inessa [10]

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