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4 years ago

6

Evaluate 3 over 2y-3 + 5 over 3z when y=6 and z=3.

1 answer:

anastassius [24]4 years ago

3 0

Answer:

$\frac{8}{9}Step-by-step explanation:[tex]\frac{3}{2y-3} + \frac{5}{3z}$ y = 6, z = 3

Substitute values into the expression:

$\frac{3}{2(6)-3} + \frac{5}{3(3)}$

Simplify both fractions:

$\frac{3}{9} + \frac{5}{9}$

Add the fractions:

[tex]\frac{8}{9}

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How do I find the possible values of x

g100num [7]

The 2 triangles in the big triangle are similar so we can write
3x / 3x - 2 = 5x / 3x

9x^2 = 15x^2 - 10x
6x^2 - 10x = 0
x(6x - 10) = 0
x= 0 or 5/3

4 0

3 years ago

Anyone want to help me!?!?!?!

Tresset [83]

Answer:

368 in^2

Step-by-step explanation:

To find the entire surface area, do the following:

Find the area of the base and then multiply it by 2:

(6 in)(5 in)(2) = 60 in^2

Find the area of one side and then mult. it by 2: then find the area of the other side and mult. that by 2 also. Add together these 3 results:

(6 in)(14 in)(2) + (5 in)(14 in)(2) + 60 in^2 = 368 in^2

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3 years ago

Is it possible to factor the equation x2+36

BlackZzzverrR [31]

Answer: 2x + 36 = 38x. Or, you find what ”x” is and go from there

Step-by-step explanation: for example, (”x” = 3) 2x3=6+36=42

5 0

3 years ago

A staircase has an angle of elevation of 28° anı

AveGali [126]

Hi there!

We can use right-triangle trigonometry to solve.

We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.

cosθ = Adjacent/Hypotenuse

We can plug in what is given:

cos(28) = A/17

Solve for 'A':

17cos(28) = <u>15.01 ft</u>

5 0

3 years ago

Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi

Viktor [21]

Answer:

The expected cost is $8.75

<em></em>

Step-by-step explanation:

Given

$Time = \{1pm, 2pm, 3pm, 4pm\}$

$C_1 = \$5$ --- If Bob and Anna meet

$C_2 = \$10$ --- If Bob and Anna do not meet

Required

The expected cost of Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

$(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)$ $,(3,4),(4,1),(4,2),(4,3),(4,4)\}$

$n(Bob, Anna) = 16$

The outcome of them meeting at the same time is:

$Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}$

$n(Same\ Time) = 4$

The probability of them meeting at the same time is:

$Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}$

$Pr(Same\ Time) = \frac{4}{16}$

$Pr(Same\ Time) = \frac{1}{4}$

The outcome of them not meeting:

$Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)$

$,(3,4),(4,1),(4,2),(4,3)\}$

$n(Different) = 12$

The probability of them meeting at the same time is:

$Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}$

$Pr(Different) = \frac{12}{16}$

$Pr(Different) = \frac{3}{4}$

The expected cost is then calculated as:

$Expected = C_1 * P(Same) + C_2 * P(Different)$

$Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}$

$Expected = \frac{\$5}{4} + \frac{\$30}{4}$

Take LCM

$Expected = \frac{\$5+\$30}{4}$

$Expected = \frac{\$35}{4}$

$Expected = \$8.75$

<em>The expected cost is $8.75</em>

4 0

3 years ago